Question

please solve this problem​

Answer 1

Answer:

Step-by-step explanation:

$Sin(A+B)=SinACosB+CosASinB\\\\From\\ABC\;and\;PQR\\\\CosA=\frac{2}{\sqrt{5}}\\\\and\\\\SinB=\frac{1}{\sqrt{10}}\\\\Now\\\\Sin (A +B)=(\frac{1}{\sqrt{5}})(\frac{3}{\sqrt{10}})+(\frac{2}{\sqrt{5}})(\frac{1}{\sqrt{10}})\\\\Sin(A+B)=\frac{5}{\sqrt{50}}\\\\Sin(A+B)=\frac{1}{\sqrt{2}}\\\\Sin(A+B)=Sin45^0\\\\A+B=45^0\\\\Hence\;Proved$

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