Chemistry, asked by parth9367, 11 months ago

please solve this problem

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Answered by Anonymous07

Answer: 2-propyl,but-1,3-diene

parth9367: ok then

Anonymous07: then we can can't leave the other double bonded carbon beacuse it has higher prority than subsituents

Anonymous07: so we end up the counting in the other double bond to ch2

parth9367: but i have been taught to select the longest chain of carbon atoms

Anonymous07: Yes, It's correct we choose the longest chain of carbon

Anonymous07: but

Anonymous07: when higher priority group like functional group or double bond/triple bond comes then we prioritize priority group

parth9367: ok

parth9367: thanks

Anonymous07: My Pleasure...

Answered by vivek832055

Answer:

2-propylbut-1,3-diene

parth9367: can u explain how

vivek832055: we have to choose the chain in which maximum no. of multiple bond is present. Now numbering is from right direction to get propyl at locant 2

parth9367: we have to choos the longest carbon chain

vivek832055: no first we have to choose the carbon chain in which highest no. of functional gp. is present 2)max. no. of muptiple bond 3)longest chain 4)highest no. of side chains

parth9367: ☺☺☺

vivek832055: i think it is clear to u

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