Please solve this problem and explain it to me
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ashusingh0015p6at0j:
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the answer of this question is 1/2
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didi
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Assume theta as alpha because I cannot type theta neither from symbols list provided here.
Given, cos²α-sin²α=1/2 ⇒ cos2α=1/2 (∵ from identity we know)
2α=60°⇒α=30°
Now, cosα^4-sinα^4= (cos30°)^4-(sin30°)^4 = (√3/2)^4-(1/2)^4 =1/2.
Given, cos²α-sin²α=1/2 ⇒ cos2α=1/2 (∵ from identity we know)
2α=60°⇒α=30°
Now, cosα^4-sinα^4= (cos30°)^4-(sin30°)^4 = (√3/2)^4-(1/2)^4 =1/2.
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