please solve this problem as fast as you can please.
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Khanhuzaifa:
bro can u mention the class
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pls see the attached
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Given sinA=(3/5) and sinB=(4/5)
And also given angle A and B are in 2nd quadrant
So cosA=(-4/5) and cosB=(-3/5)
So 4cosA + 3cosB = (-5)
And also given angle A and B are in 2nd quadrant
So cosA=(-4/5) and cosB=(-3/5)
So 4cosA + 3cosB = (-5)
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