Math, asked by chiragpunmia, 1 year ago

Please solve this problem as soon as possible

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Answers

Answered by starock20kamalrock
0
hope it helps you....
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Answered by saisanjay123
1
x-5=0
x=5
sub x=5 in f(x)
(5)^3+m(5)^2+n(5)-20=0
125+25m+5n-20=0
25m+5n=-105
5m+n=-21---------(1)
x-3=0
x=3
sub x=3 in f(x)
(3)^3+m(3)^2+n(3)-20=-2
27+9m+3n-20=-2
9m+3n=-9
3m+n=-3--------(2)
-5m-n=-21
---------
-2m=-24
m=12
3(12)+n=-3
n=-3-36
n=-39
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