Math, asked by sharwanyadav1014, 23 days ago

please solve this problem class 10 chapter 8 introduction to trigonometry maths​

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Answered by harshb77
0

Step-by-step explanation:

(7) \:  \:  \:  \:  \:  \: tan(θ) = 2  -   \sqrt{3}  \\ now \: tan(θ) \times cot(θ) = 1 \\ cot(θ) =  \frac{1}{tan(θ)}  \\ cot(θ) =  \frac{1}{2 -  \sqrt{3} }  \\ cot(θ) =  \frac{1 \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: (2 +  \sqrt{3}) }{(2 -  \sqrt{3})(2 +  \sqrt{3} ) }  \\ cot(θ) =   \frac{2 +  \sqrt{3} }{ {2}^{2}  -  { (\sqrt{3}) }^{2} }  \\ cot(θ) =  \frac{2 +  \sqrt{3} }{4 - 3}  \\ cot(θ) = 2 +  \sqrt{3} \\ (8) \:  \: sec²(θ)+cosec²(θ)= \frac{1}{cos²(θ)}  +  \frac{1}{sin²(θ)}  \\  =  \frac{sin²(θ)+cos²(θ)}{sin²(θ) \times cos²(θ)}  \\  = sec²(θ) \times cosec²(θ)

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