Question

please solve this problem
Do it in a paper ​

Answer 1

Question :-

$\bf \:3x + {23x}^{2} + {6y}^{2} + 2x + {y}^{2} + ...... = 5x + {7y}^{2}$

Solution :-

Let the fill in the blank be 'k'.

$\bf \:3x + {23x}^{2} + {6y}^{2} + 2x + {y}^{2} + k= 5x + {7y}^{2}$

$\bf\implies \:\bf \:5x + {23x}^{2} + {7y}^{2} + k = 5x + {7y}^{2}$

$\bf\implies \:k = 5x + {7y}^{2} - 5x - {7y}^{2} - {23x}^{2}$

$\bf\implies \:k = { - 23x}^{2}$

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Answer 2

${\large{\sf{QUESTION\: :}}}$

${\sf{3x + {23x}^{2} + {6y}^{2} + 2x + {y}^{2} + .... = 5x + {7y}^{2}}}$

${\large{\sf{SOLUTION \: :}}}$

Let the blank be 'z'.

${\sf{3x + {23x}^{2} + {6y}^{2} + 2x + {y}^{2} + z = 5x + {7y}^{2}}}$

$→ {\sf{5x + {23x}^{2} + {7y}^{2} + z = 5x + {7y}^{2}}}$

$→ {\sf{z = 5x + {7y}^{2} - 5x - {7y}^{2} - {23x}^{2}}}$

$→ {\sf{z = { - 23x}^{2}}}$

${\sf{Therefore,\:}{3x + {23x}^{2} + {6y}^{2} + 2x + {y}^{2} + {\underline{{- 23x}^{2}} = 5x + {7y}^{2}}}}$