Question

please solve this problem
explain also​

Answer 1

Answer:

Is the answer of tis question 0

Answer 2

Answer:

The value is $\dfrac{10}{3}$  .

Step-by-step explanation:

We need to find

$\dfrac{2^{2001}+2^{1999}}{2^{2000}+2^{1998}}$

Here $2^{1999}$  is a common factor of both terms in numerator and $2^{1998}$ is a common factor of both terms in denominator. Taking the common factors separately, we get

$\dfrac{2^{1999}(2^2+1)}{2^{1998}(2^2-1)} = \dfrac{2\times (4+1)}{4-1} =\dfrac{10}{3}$

(Note that   $\dfrac{2^{1999}}{2^{1998}} = 2^{1999-1998}=2^1=2$  )