Math, asked by npvidya16, 1 year ago

please solve this problem fast.

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Answers

Answered by siddhartharao77
1
Given that length = 75m.

                  breadth = 60m.

                  height = 16m.


Given that Area of  1 door = 4 * 3 = 12m^2.

Then the area of total 5 doors = 12 * 5 = 60m^2.

Given that Area of one window = 3 * 1.6 = 4.8m^2.

Then the area of total four windows = 4.8 * 4 = 19.2m^2.


(1) Papering its walls at the rate of 12 per m^2.

We know that A = 2(l + b) * h

                            = 2(75 + 60) * 16

                            = 270 * 16

                            = 4320m^2.


Area of the walls to be papered = Area of dining hall - (Area of 5 doors + Area of 4 windows)

 = 4320 - (60 + 19.2)

= 4320 - 79.2

= 4240.8m^2.


Given that cost of papering the walls = 12 per m^2.

= 4240.8 * 12

= 50889.6

Therefore the total cost = 50889.6 rupees.


(2).Carpeting its floor at the rate of 23 per m^2.

Area = l * b

         = 75 * 60

         = 4500.

Given that carpeting cost per m^2 = 25.

= 4500 * 25

= 112500.


Therefore the total cost = 112500 rupees.


Hope this helps!

npvidya16: thank you so much
siddhartharao77: My Pleasure
siddhartharao77: Thanks vidya for the brianliest
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