Question

please solve this problem fast ​

Answer 1

Answer:

Value of q is 9

As we know when proportional sign is replaced by '’=” then a proportional constant comes in the equation hence

Where k is constant

Solve for k

$p = k \times \frac{1}{ \sqrt{q} } \\ 6 = k \times \frac{1}{ \sqrt{4} } \\ 6 = k \times \frac{1}{2} \\ k = 12$

When p= 4 then

$p = k \times \frac{1}{ \sqrt{q} } \\ 4 = 12 \times \frac{1}{ \sqrt{q} } \\ \sqrt{q} = \frac{12}{4} \\ q = {3}^{2} \\ q = 9$