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Answers
Answer:
Answer:
Given :-
A body moving with velocity 40 m/s is brought to rest in 20 seconds.
To Find :-
What is the retardation and the distance travelled by a body.
Formula Used :-
❶To find acceleration we know that,
\boxed{\bold{\large{v\: =\: u\: +\: at}}}
v=u+at
❷ To find distance travelled we know that,
\boxed{\bold{\large{{v}^{2} =\: {u}^{2} +\: 2as}}}
v
2
=u
2
+2as
where,
v = Final velocity
u = Initial velocity
a = Acceleration
t = Time
s = Distance travelled
Solution :-
❶ To find retardation,
Given :
Final velocity = 0 m/s
Initial velocity = 40 m/s
Time = 20 seconds
According to the question by using the formula we get,
⇒ 0 = 40 + a(20)
⇒ 0 - 40 = 20a
⇒ - 40 = 20a
⇒ \dfrac{\cancel{- 40}}{\cancel{20}}
20
−40
= a
⇒ - 2 = a
➠ a = - 2 m/s²
\therefore∴ The retardation of a body is - 2 m/s² .
❷ To find distance travelled,
Given :
Final velocity = 0 m/s
Initial velocity = 40 m/s
Time = 20 seconds
Acceleration = - 2 m/s²
According to the question by using the formula we get,
↦ (0)² = (40)² + 2(- 2) × s
↦ 0 = 1600 - 4 × s
↦ 0 = 1600 - 4s
↦ 0 - 1600 = - 4s
↦ - 1600 = - 4s
↦ \dfrac{\cancel{- 1600}}{\cancel{- 4}}
−4
−1600
= s
↦ 400 = s
➥ s = 400 m
\therefore∴ The distance travelled by a body is 400 m .Answer:
Given :-
A body moving with velocity 40 m/s is brought to rest in 20 seconds.
To Find :-
What is the retardation and the distance travelled by a body.
Formula Used :-
❶To find acceleration we know that,
\boxed{\bold{\large{v\: =\: u\: +\: at}}}
v=u+at
❷ To find distance travelled we know that,
\boxed{\bold{\large{{v}^{2} =\: {u}^{2} +\: 2as}}}
v
2
=u
2
+2as
where,
v = Final velocity
u = Initial velocity
a = Acceleration
t = Time
s = Distance travelled
Solution :-
❶ To find retardation,
Given :
Final velocity = 0 m/s
Initial velocity = 40 m/s
Time = 20 seconds
According to the question by using the formula we get,
⇒ 0 = 40 + a(20)
⇒ 0 - 40 = 20a
⇒ - 40 = 20a
⇒ \dfrac{\cancel{- 40}}{\cancel{20}}
20
−40
= a
⇒ - 2 = a
➠ a = - 2 m/s²
\therefore∴ The retardation of a body is - 2 m/s² .
❷ To find distance travelled,
Given :
Final velocity = 0 m/s
Initial velocity = 40 m/s
Time = 20 seconds
Acceleration = - 2 m/s²
According to the question by using the formula we get,
↦ (0)² = (40)² + 2(- 2) × s
↦ 0 = 1600 - 4 × s
↦ 0 = 1600 - 4s
↦ 0 - 1600 = - 4s
↦ - 1600 = - 4s
↦ \dfrac{\cancel{- 1600}}{\cancel{- 4}}
−4
−1600
= s
↦ 400 = s
➥ s = 400 m
\therefore∴ The distance travelled by a body is 400 m .Answer:
Given :-
A body moving with velocity 40 m/s is brought to rest in 20 seconds.
To Find :-
What is the retardation and the distance travelled by a body.
Formula Used :-
❶To find acceleration we know that,
\boxed{\bold{\large{v\: =\: u\: +\: at}}}
v=u+at
❷ To find distance travelled we know that,
\boxed{\bold{\large{{v}^{2} =\: {u}^{2} +\: 2as}}}
v
2
=u
2
+2as
where,
v = Final velocity
u = Initial velocity
a = Acceleration
t = Time
s = Distance travelled
Solution :-
❶ To find retardation,
Given :
Final velocity = 0 m/s
Initial velocity = 40 m/s
Time = 20 seconds
According to the question by using the formula we get,
⇒ 0 = 40 + a(20)
⇒ 0 - 40 = 20a
⇒ - 40 = 20a
⇒ \dfrac{\cancel{- 40}}{\cancel{20}}
20
−40
= a
⇒ - 2 = a
➠ a = - 2 m/s²
\therefore∴ The retardation of a body is - 2 m/s² .
❷ To find distance travelled,
Given :
Final velocity = 0 m/s
Initial velocity = 40 m/s
Time = 20 seconds
Acceleration = - 2 m/s²
According to the question by using the formula we get,
↦ (0)² = (40)² + 2(- 2) × s
↦ 0 = 1600 - 4 × s
↦ 0 = 1600 - 4s
↦ 0 - 1600 = - 4s
↦ - 1600 = - 4s
↦ \dfrac{\cancel{- 1600}}{\cancel{- 4}}
−4
−1600
= s
↦ 400 = s
➥ s = 400 m
\therefore∴ The distance travelled by a body is 400 m .
Answer:
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