please solve this problem for 15 points
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Answered by
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the answer is A=58° BY USING PROPERTY
FIRST U HAVE TO DIVIDE BOTH NUMERATOR AND DENOMINATOR BY COS13°
AFTER THAT YOU GET 1+TAN13°/1-TAN13°
IT IS PROPERTY THAT 1+TANA/1-TANA=TAN(45°+A)
WHICH IS EQUAL TO TAN(45°+13°)
=tan(58°)
so A is 58°
FIRST U HAVE TO DIVIDE BOTH NUMERATOR AND DENOMINATOR BY COS13°
AFTER THAT YOU GET 1+TAN13°/1-TAN13°
IT IS PROPERTY THAT 1+TANA/1-TANA=TAN(45°+A)
WHICH IS EQUAL TO TAN(45°+13°)
=tan(58°)
so A is 58°
Urvish19:
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Answered by
4
Divide by cos 13 in numerator and denominator
( 1 + tan 13 ) / ( 1 - tan 13 )
we can write this as :-
( tan 45 + tan 13 ) / ( 1 - tan 45 tan 13 )
tan ( 45 + 13 )
tan 58 = tan A
hence A will be 58 degree .
( 1 + tan 13 ) / ( 1 - tan 13 )
we can write this as :-
( tan 45 + tan 13 ) / ( 1 - tan 45 tan 13 )
tan ( 45 + 13 )
tan 58 = tan A
hence A will be 58 degree .
in yours to i dont understand
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