Question

please solve this problem given​

Answer 1

Step-by-step explanation:

Fig 6.43

Angle QRT = Angle RQS + Angle OSR

(Ext. angle of triangle = sum of two opp. int. angles)

Let angle QSR be x.

65 = 28 + x

Angle QSR = x = 37

Given PQ || SR,

So, x = Angle QSR = 37

(alternate int. angles)

In triangle PSO,

x + y + 90 = 180 (angle sum property of traingle)

y + 90 + 37 = 180

y = 53