Question

Please solve this problem in a different sheet!! Thank you in advance for your help!!

Answer 1

↑ Here is your answer ↓
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$d = 28 cm$

$r = 14 cm$

Volume of a cone,

$1/3 \pi r^2 h = 9856$

$\pi r^ h = 29568$

$r^h = 29568 * 7/22$

$r^h = 9408$

$(14)^2 * h = 9408$

$196 * h - 9408$

$h = 9408/196$

$h = 48 cm$

Now the slant height of the cone,

$l = \sqrt{h^2 + r^2}$

$l = \sqrt{48^2 + 14^2}$

$l = \sqrt{2304 + 196}$

$l = \sqrt{2500}$

$l = 50cm$

Now the curved surface area,

$= \pi r l$

$= 22/7 * 14 * 50$

$= 2200 cm^2$

Answer 2

Given Volume of a cone = 9856cm^3.

Given Diameter of base = 28cm.

Then radius = 14cm.

We know that volume of cone = 1/3pir^2h.

9856 = 1/3 * (22/7) * (14)^2 * h

9856 = 1/3 * 22/7 * 14 * 14 * h

h = 9856 * 3 * 7/22 * 196

h = 206976/4312

h =  48cm.


Therefore the height of the cone = 48cm.


Slant height of the cone l^2 = h^2 + r^2

                                                = 48^2 + 14^2

                                                = 2304 + 196

                                                = 2500


                                          l = 50cm.


(ii)

We know that curved surface area of the cone = pirl

                                                                               = 22/7 * 14 * 50

                                                                                = 2200cm^2.


Therefore the curved surface area of the cone = 2200cm^2.


Hope this helps!