Question

↔ Please solve this problem

❎❌❎ NO SPAMS ALLOWED

Answer 1

CaCO3 -----> CaO + CO2
1 mole CaCO3 gives 1 mole CO2
100g CaCo3 gives 44g CO2
So, 22g of CO2 will be given by 50g CaCO3

But CaCO3 is 90% pure
So, CaCO3 needed will be 50 + 10*50/100 = 55g

So, 55g CaCO3 will be needed to produce 22g CO2.

Answer 2

1 mole CaCO3 produces 1 mole CO2 so 100g of CaCo3 will give 44g of CO2therefore 22g of CO2  = 44/100*22 = 50 g of CO2
CaCO3 =90% pureCaCO3 needed =  90*100/50 = 45g