Question

please solve this problem of 4th please do it fast.

Answer 1

Hey!!!

As promised I am here to help you

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let the number of Oranges with A be x and that with B be y

Then ATQ,

=> x + 10 = (y - 10)2

=> x + 10 = 2y - 20

=> x - 2y = -30 -------(1)

Also

=> x - 10 = y + 10 (same number left)

=> x = y + 20 ------(2)

Substituting (2) in (1)

=> y + 20 - 2y = -30

=> -y = -50

=> y = 50 <<<<<< Answer

Using y in (2)

=> x = 50 + 20

=> x = 70 <<<<<<<< Answer

Thus A has 70 oranges and B has 50 oranges

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Hope this helps ✌️

Legally Good Morning :-)

Study Harder

Answer 2

Let's assume that A and B has "A" and "B" number of oranges.

Now according to the question.

[A+10]=2[B-10}
2B-A=30...............(i) and

[A-10}=[B+10}
B-A= -20...........(ii)

Substracting eq(ii) from eq (i), we get
B=50
Substitutin the value of B in eq(i) we get,
A=70

So, A has 70 Oranges and B has 50 Oranges.