Question

please solve this problem of maths . solve 9th one please.

( Note - Irrelevant answer will be reported.)​

Answer 1

Answer:

80°

Step-by-step explanation:

A+B+C+D=360°

A+B+100°+60°=360°

A+B=200°

AP and AB bisect A and B

So PAB+PBA=200/2=100°(PAB=½A PBA=½B)

PAB+PBA+APB=180°(Sum of angles in a triangle)

100+ABP=180°

ABP=80°

Answer 2

A+B+C+D=360°

A+B+100°+60°=360°

A+B=200°

AP and AB bisect A and B

so PAB + PBA = 200/2 = 100°

PAB+PBA+APB=180°

100+APB = 180°

APB =180-100=80°

APB = 80°

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