Question

please solve this problem p please​

Answer 1

||✪✪ CORRECT QUESTION ✪✪||

if 2^(5x) ÷ 2^x = 5√2^(20)

find x ?

|| ✰✰ ANSWER ✰✰ ||

→ 2^(5x) ÷ 2^x = 5√2^(20)

→ 2^(5x) / 2^x = 5√2^(20)

using (a^b) /(a^c) = a^(b - c) in LHS now, we get,

→ 2^(5x - x) = 5√2^(20)

→ 2^(4x) = 5√2^(20)

Now, using n√a = (a)^(1/n) in RHS, we get,

→ 2^(4x) = [(2)^20]^(1/5)

Now using (a^m)^n = (a)^mn in RHS , we get,

→ 2^(4x) = (2)^(20*1/5)

→ 2^(4x) = (2)^4

Now we know that, if a^b = a^c than b = c .

So,

→ 4x = 4

→ x = 1 (Ans).

Answer 2

Solution is in the attachment.