Math, asked by mynameamitpatwal, 9 months ago

please solve this problem . please​

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Answers

Answered by ankitsharma7734
1

Answer:

(x - √6)(√3 x +√2)

Step-by-step explanation:

√3 x^2 - 2√2 x - 2√3 = 0

√3 x^2 - ( 3√2 - √2 )x -2√3 = 0

√3 x^2 -3√2 x + √2 x - 2√3 = 0

√3 x(x - √6) + √2(x - √6) = 0

(x - √6)(√3 x +√2)

Answered by Anonymous
1

Step-by-step explanation:

√3x²- 2√2x - 2√3=0

√3x²- ( 3√2- √2 )x -2√3=0

√3x² - 3√2x + √2x - 2√3 = 0

√3x ( x-√6) + √2 ( x-√6 ) = 0

( x-√6) ( √3x+√2)=0

here,

x = √6. , x = -√2/√3

here we neglected -√2/√3 then our answer is √6..

pls mark me as a brainlist......☺☺

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