Question

please solve this problem please help me ​

Answer 1

Force along straight line = 20 cos 30° = 20√3/2 =17.32 N

Normal reaction on the body =n =5×10 = 50 N

Weight of the body = mg= 50 N

Limiting friction force acting on the body= 0.25×5×10= 12.5 N

So, total external force acting is = 17.32 - 12.5 = 4.82 N

So, Acceleration = 4.82/5 = 0.964 m/s^2