Question

please solve this problem quick x+2/6-(11-x/3-1/4)=3x-4/12

Answer 1

Step 1 :

1
Simplify —
3
Equation at the end of step 1 :

2 x 1 1
((x+—)-((11-—)-—))-(3x-—) = 0
6 3 4 3
Step 2 :

Rewriting the whole as an Equivalent Fraction :

2.1 Subtracting a fraction from a whole

Rewrite the whole as a fraction using 3 as the denominator :

3x 3x • 3
3x = —— = ——————
1 3
Equivalent fraction : The fraction thus generated looks different but has the same value as the whole

Common denominator : The equivalent fraction and the other fraction involved in the calculation share the same denominator

Adding fractions that have a common denominator :

2.2 Adding up the two equivalent fractions
Add the two equivalent fractions which now have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

3x • 3 - (1) 9x - 1
———————————— = ——————
3 3
Equation at the end of step 2 :

2 x 1 (9x-1)
((x+—)-((11-—)-—))-—————— = 0
6 3 4 3
Step 3 :

1
Simplify —
4
Equation at the end of step 3 :

2 x 1 (9x-1)
((x+—)-((11-—)-—))-—————— = 0
6 3 4 3
Step 4 :

x
Simplify —
3
Equation at the end of step 4 :

2 x 1 (9x-1)
((x+—)-((11-—)-—))-—————— = 0
6 3 4 3
Step 5 :

Rewriting the whole as an Equivalent Fraction :

5.1 Subtracting a fraction from a whole

Rewrite the whole as a fraction using 3 as the denominator :

11 11 • 3
11 = —— = ——————
1 3
Adding fractions that have a common denominator :

5.2 Adding up the two equivalent fractions

11 • 3 - (x) 33 - x
———————————— = ——————
3 3
Equation at the end of step 5 :

2 (33-x) 1 (9x-1)
((x+—)-(——————-—))-—————— = 0
6 3 4 3

Answer 2

Step-by-step explanation:

$\mathsf{Given : \dfrac{x + 2}{6} - \bigg(\dfrac{11 - x}{3} - \dfrac{1}{4}\bigg) = \dfrac{3x - 4}{12}}$

$\mathsf{\implies \dfrac{x + 2}{6} - \bigg(\dfrac{4(11 - x) - 3}{12}\bigg) = \dfrac{3x - 4}{12}}$

$\mathsf{\implies \dfrac{x + 2}{6} - \bigg(\dfrac{44 - 4x - 3}{12}\bigg) = \dfrac{3x - 4}{12}}$

$\mathsf{\implies \dfrac{x + 2}{6} - \bigg(\dfrac{41 - 4x}{12}\bigg) = \dfrac{3x - 4}{12}}$

$\mathsf{\implies \bigg(\dfrac{x + 2}{6} - \dfrac{(41 - 4x)}{12}\bigg) = \dfrac{3x - 4}{12}}$

$\mathsf{\implies \dfrac{2(x + 2) - (41 - 4x)}{12} = \dfrac{3x - 4}{12}}$

$\mathsf{\implies \dfrac{2x + 4 - 41 + 4x}{12} = \dfrac{3x - 4}{12}}$

$\mathsf{\implies \dfrac{-37 + 6x}{12} = \dfrac{3x - 4}{12}}$

$\mathsf{\implies {-37 + 6x} = {3x - 4}}$

$\mathsf{\implies 6x - 3x = 37 - 4}$

$\mathsf{\implies 3x = 33}$

$\mathsf{\implies x = \dfrac{33}{3}}$

$\mathsf{\implies x = 11}$