Question

please solve this problem so urgent​

Answer 1

Answer:

14,14 & 12

Step-by-step explanation:

n(U)=40

n(T)[Students playing Tennis]=28

n(B)[Students playing Badminton]=26

Now,

Students playing both games=n(T∩B)

We know,

N(U)=n(TUB)+N(TUB)Complementary

Since each student plays atleast one N(TUB)Complementary=0

So,

N(U)=n(T)+n(B)-n(T∩B)

or,40=28+26-n(T∩B)

or,40-54=-n(T∩B)

or,-14=-n(T∩B)

Therefore, n(T∩B)=14

Again,

For only one games,

nonly(T)=n(T)-n(T∩B)=28-14=14

nonly(B)=n(B)-n(T∩B)=26-14=12

Answer 2

Step-by-step explanation:

The answer is attached above. I hope you have understood the question.