Question

Please solve this puzzle in the image given below

Answer 1

Answer:

Take these Numbers in the term of Alphabet. Let Blue be A, White be B, Red be C and Puzzel will be :

⋆ ABC + ABC + ABC = CCC

& these are Number, so we can write in Expanded Form be :

⇢ 3(100A + 10B + C) = 100C + 10C + C

⇢ 300A + 30B + 3C = 111C

⇢ 300A + 30B = 111C – 3C

⇢ 300A + 30B = 108C

⇢ 6(50A + 5B) = 108C

• Dividing both term by 6

⇢ 50A + 5B = 18C

⇢ 5(10A + B) = 18C

⇢ 10A + B = 18C/5

• we know that A, B & C are Whole Number, and according to situation C should must be a multiplie of 5.
• Since 0 < C ≤ 9, therefore C = 5

⇢ 10A + B = (18 × 5)/5

⇢ 10A + B = 18

⇢ 10A + B = (10 × 1) + 8

• Comparing Both

⇢ A = 1⠀and,⠀B = 8

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☯ We Have :

⇾ A = 1 [ Blue ]

⇾ B = 8 [ White ]

⇾ C = 5 [ Red ]

∴ Value of blue, white & red is 1, 8 & 5.

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☢ VERIFICATION :

⟶ ABC + ABC + ABC = CCC

⟶ 185 + 185 + 185 = 555

⟶ 555 = 555 Hence, Verified!

Answer 2

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$\huge\tt{GIVEN:}$

• A puzzle to be solved

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$\huge\tt{SOLUTION:}$

Let the Blue ball be X

Let the Red ball be Y

Let the Grey ball be Z

So,we could make an equation,

➩3 [ 100x + 10y + z] = 100y + 10y + y

➩3 [100x + 10y + z ] = 111y

➩100x + 10y + z = 37y

➩100x + z = 27y

One possible answer is if we let x = 1 and z = 8, then y = 4

➩100(1) + 8 = 27(4)

➩108 = 108

➩148 + 148 + 148 = 444

Then,

x/blue ball = 1

y/Red ball = 4

z/ Grey ball = 8

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