Math, asked by ArkaDey, 10 months ago

please solve this quadratic equation ​

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Answers

Answered by shivaranjani1218
1

Step-by-step explanation:

1. x=√3

substitute in given eq

(√3)²-3√3(√3)+6

3-9+6

6-6=0

x=-2√3

substitute in given eq

(-2√3)²-3√3(-2√3)+6

12-3(-6)+6

12+18+6

36

√3 is the solution of the given eq

2.x=-√2

substitute in given eq

(-√2)²-√2(-√2)-4

2+2-4

4-4

0

x=2√2

substitute in given eq

(2√2)²-√2(2√2)-4

8-4-4

8-8

0

√2 and 2√2 are the solution's of given eq

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