please solve this quadratic equation
Attachments:
Answers
Answered by
1
Step-by-step explanation:
1. x=√3
substitute in given eq
(√3)²-3√3(√3)+6
3-9+6
6-6=0
x=-2√3
substitute in given eq
(-2√3)²-3√3(-2√3)+6
12-3(-6)+6
12+18+6
36
√3 is the solution of the given eq
2.x=-√2
substitute in given eq
(-√2)²-√2(-√2)-4
2+2-4
4-4
0
x=2√2
substitute in given eq
(2√2)²-√2(2√2)-4
8-4-4
8-8
0
√2 and 2√2 are the solution's of given eq
Similar questions