Question

Please solve this quadratic equation------4(2x-3)^2-(2x-3)-14

Answer 1

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Here's your answer...

Let 2x-3 = y
Then the equation becomes 4y²-y-14 = 0
4y²-8y+7y-14 = 0
4y(y-2)+7(y-2) = 0
(4y+7)(y-2) = 0
y = 2 or - 7/4
2x-3 = 2 or - 7/4
2x = 5 or 5/4
x = 5/2 or 5/8

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