Question

please solve this quadratic equation

Answer 1

Hope it helps.........

Answer 2

Answer:

$\frac{1}{2a + b + 2x} = \frac{1}{2a} + \frac{1}{b} + \frac{1}{2x} \\ \frac{1}{2a + b + 2x} - \frac{1}{2x} = \frac{1}{2a} + \frac{1}{b} \\ \frac{2x - 2a - b - 2x}{(2a + b + 2x)(2x)} = \frac{b + 2a}{2ab} \\ \frac{ - (2a + b)}{(2a + b + 2x)(2x)} = \frac{b + 2a}{2ab} \\ \frac{ - 1}{(2a + b + 2x)(2x)} = \frac{1}{2ab} \\ - 2ab = 4ax + 2bx + 4 {x}^{2} \\ 2ab + 4ax + 2bx + 4 {x}^{2} = 0 \\ 2a(b + 2x) + 2x(b + 2x) = 0 \\ (b + 2x)(2a + 2x) = 0 \\ = > x = - \frac{b}{2} \: or \: x = - a$