please solve this quadratic equation -x²+x+156=0
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Answer:
Step-by-step explanation:
x²-x-156 =0
x²-13x+12x-156 =0
x(x-13)+12(x-13)=0
(x-13)(x+12)=0
x-13 = 0 , x+12 =0
x=13 ,x= -12
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