please solve this que...please please please
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[tex]\huge\boxed{ANSWER:-}[/tex}
★ Applying law of conservation of energy,
★ ∆E = work done = {(k.E)f + (P.E)f } - (K.E)i + {(P.E)i}
★ initial K.E = 1/2mv^2 = 1/2 ×3 × 2 × 2 = 6j
initial P.E = mgh = 3 × 10× 4 = 120 j
★ final K.E = 1/2 × 3 × 6 × 6 = 54j
P.E final = mgh = 3 × 10 × 1 = 30j
●【putting the values in above formula 】
work done = ∆E = (126 - 84)j = 42j
©orrect answer is option 1
happy to help !
:)
★ Applying law of conservation of energy,
★ ∆E = work done = {(k.E)f + (P.E)f } - (K.E)i + {(P.E)i}
★ initial K.E = 1/2mv^2 = 1/2 ×3 × 2 × 2 = 6j
initial P.E = mgh = 3 × 10× 4 = 120 j
★ final K.E = 1/2 × 3 × 6 × 6 = 54j
P.E final = mgh = 3 × 10 × 1 = 30j
●【putting the values in above formula 】
work done = ∆E = (126 - 84)j = 42j
©orrect answer is option 1
happy to help !
:)
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