Question

please solve this ques

Answer 1

Question:

Find the value of b if x + 1 is a factor of bx⁻³ + x² - 2x + 4b - 9

Answer:

We have been given that x + 1 is a factor of the expression.

That means,

x + 1 = 0

x = -1

That means -1 is a root of the given expression and the expression would be equated to zero when the value of 'x' is substituted.

Substitute the value of x in the expression:-

b(1)⁻³ + (1)² - 2(1) + 4b - 9 = 0

b + 1 - 2 + 4b - 9 = 0

Add the like terms:-

5b - 10 = 0

Transposing:-

5b = 10

b = $\frac{10}{5}$

b = 2

So, the value of b is 2 !

$\large\boxed{\large\boxed{\large\boxed{Solved !}}}}$

Answer 2

Given polynomial :

bx³+x²-2x+4b-9

b(x+1) => x = -1

b(-1)³+(-1)²-2(-1)+4b -9

-b+1+2+4b-9

-b+3+4b-9

3b+3-9

As it is given as the factor , so the remainder is equal to 0 .

3b+3-9 = 0

3b+3 = 9

3b = 9-3

3b = 6

b = 6/3

b = 2