please solve this ques please
Class 10
Circles
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Hii !!!
Solution is in this given attachment !!!
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Hope it helps !!!
#Muskraj ❤
Solution is in this given attachment !!!
____________________________
Hope it helps !!!
#Muskraj ❤
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As : ABC is a Right Angled Triangle
According to Pythagorean Theorem :
(Hypotenuse)² = (1st Leg)² + (2nd Leg)²
Here : AC is the Hypotenuse and AB and BC are two legs
⇒ (AC)² = (AB)² + (AC)²
Given : AB = 8 and BC = 6
⇒ (AC)² = 8² + 6²
⇒ (AC)² = (64 + 36) = 100
⇒ AC = 10 cm
We know that : Lengths of Tangents drawn from an External Point to a Circle are Equal
⇒ CD = CF
From the Diagram, We can Notice that : CF = BC - r
⇒ CF = 6 - r
In the Similar way : AD = AE and AE = AB - r
⇒ AE = 8 - r
We can Notice that : AC = AD + CD
But : AD = AE and CD = CF
⇒ AC = AE + CF
⇒ 10 = (8 - r) + (6 - r)
⇒ 10 = 14 - 2r
⇒ 2r = 4
⇒ r = 2cm
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