Math, asked by minny31, 11 months ago

please.solve this question ❓❓​

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Answers

Answered by tejas276
0

Answer:

70 + 14 \sqrt{3}

Step-by-step explanation:

 \frac{5 +  \sqrt{3} }{7 - 4 \sqrt{3} }  +  \frac{5 +  \sqrt{3} }{7 + 4 \sqrt{3} }

rationalization of denominator..

 \frac{5 +  \sqrt{3} }{7 - 4 \sqrt{3} }  \times  \frac{7 + 4 \sqrt{3} }{7 + 4 \sqrt{3} }  +  \frac{5 +  \sqrt{3} }{7 + 4 \sqrt{3} }  \frac{7 - 4 \sqrt{3} }{7 - 4 \sqrt{3} }

solve..

 \frac{(5 +  \sqrt{3})(7 + 4 \sqrt{3})  }{49 - 16 \times 3}  +  \frac{(5 +  \sqrt{3} )(7 - 4 \sqrt{3} )}{49 - 16 \times 3}

Or

 \frac{(5 +  \sqrt{3})(7 + 4 \sqrt{3})  }{49 - 48}  +  \frac{(5 +  \sqrt{3} )(7 - 4 \sqrt{3} )}{49 - 48}

Or

 (5 +  \sqrt{3})(7 + 4 \sqrt{3})   +  (5 +  \sqrt{3})(7 - 4 \sqrt{3})

Or

35 + 20 \sqrt{3}  + 7 \sqrt{3}  + 12 + 35 - 20 \sqrt{3}   - 12

Or

35 + 7 \sqrt{3}  + 35 + 7 \sqrt{3}

Add them

70 + 14 \sqrt{3}

So we reach to an End...

Hope it will help you


tejas276: thanks bhai
Answered by Anonymous
1

Answer:

14(5+√3)

Step-by-step explanation:

Attachments:

Anonymous: ok good
Anonymous: what you know about Einstien,who was Einstien. Is he an indian
Anonymous: Samajha ye gyaan tumhare kam ka bhi nahi bye,bye.................
tejas276: LOSSES YOUR AOCCS
tejas276: ;o
Anonymous: achchha to ab apni bak bas aur aukat par a gay too,bol kya chahata hai. too
Anonymous: should i call admin and delete yr account just now.
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