Question

Please solve this question ​

Answer 1

Question:

A jar contains 24 marbles, some are green and other are blue. If a marble is drawn at random from a jar, the probability that it is green is $\dfrac{2}{3}$ . Find the number of blue balls in the jar.

Solution:

Total number of outcomes = 24

Let there be x green marbles.

Therefore favourable number of outcomes = x

$\boxed{P(Any\: Event) = \dfrac{Number \: of \: favourable\: outcomes}{Number\: of \:total \:outcomes}}$

$P(Green) = \dfrac{x}{24}$

But $P(Green) = \dfrac{2}{3}$

So,

$\dfrac{x}{24} = \dfrac{2}{3}$

x = 16

Number of Green marbles = 16

Number of blue marbles = 24 - 16 = 8

Answer 2

Answer:

No of blue marbles is 8

Step-by-step explanation:

Question given,

A jar contains total of 24 marbels

Out of them some are green and others are blue

Let's assume total no of green marbles be X

and blue marbles be Y

Given,

Condition :- If a marble is drawn at random from jar the probability of green marble is $\frac{2}{3}$

As, we know :-

$Probability </em></strong><strong><em> </em></strong><strong><em>of an Event = \frac{Number </em></strong><strong><em> </em></strong><strong><em> </em></strong><strong><em>of</em></strong><strong><em> </em></strong><strong><em>Favorable Outcomes}{Total Number of Possible Outcomes}$

So, P(green) = $\frac{x}{24}$

But condition given,

P (green) = $\frac{2}{3}$

=> $\frac{x}{24} = \frac{2}{3}$

=> x = $\frac{2}{3} \times 24$

=> $\frac{48}{3}$

=> x = 16

So, no of green marbles is 16

Now, no.of blue marbles = Total no.of marbles - no.of green marbles

=> 24 - 16

=> 8