Math, asked by anuj6421, 10 months ago

please solve this question

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Answers

Answered by manjunpai2000
1

Answer:

(5^2x × 5^2 × 5^x - 5^3x)/5^3y × 2^3 = 3/5^3

(5^3x×5^2 - 5^3x)/5^3y × 2^3 = 3/5^3

5^3x(5^2 - 1)/5^3y × 2^3 = 3/5^3

5^3x(24)/5^3y × 8 = 3/5^3

5^3x(3)×5^-3y = 3/5^3

5^3x-3y = 5^-3

3x-3y = -3

x-y = -1

-(x-y) = -(-1)

y-x = 1

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