Math, asked by divyansh5237, 1 year ago

please solve this question​

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Answered by adrija70
1

Please refer to the attachment. Hope it helps

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Answered by abhi569
1

Answer:

Required numeric value of \dfrac{2^n + 2^{n-1}}{2^{n+1}-2^n} is 3 / 2.

Step-by-step explanation:

\implies \dfrac{2^n + 2^{n-1}}{2^{n+1}-2^n}

From the properties of indices :

  • a^( m + n ) = a^m x a^n
  • a^( m - n ) = a^m / a^n

Thus,

\implies \dfrac{2^n+(\frac{2^n}{2^1})}{(2^n\times2^1)-2^n}\\\\\\\implies\dfrac{2^n(1+\frac{1}{2})}{2^n(2-1)}\\\\\\\implies\dfrac{\frac{2+1}{2}}{1}\\\\\\\implies\dfrac{3}{2}

Hence the required value of \dfrac{2^n + 2^{n-1}}{2^{n+1}-2^n} is 3 / 2.

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