please solve this question!!!!
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Hi..
the distance between 2 consecutive bright or dark fringes or fringe width = λD /d
where λ is the wavelength
D = the distance where the screen is
d = length between the 2 slits
all of those are given in the question..all you have to is...just substitute the values and simplify :)
hope this will help ya :)
the distance between 2 consecutive bright or dark fringes or fringe width = λD /d
where λ is the wavelength
D = the distance where the screen is
d = length between the 2 slits
all of those are given in the question..all you have to is...just substitute the values and simplify :)
hope this will help ya :)
Anonymous:
complete ur answer
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In Young's double slit experiment, the distance between bright fringe and dark fringe = λD/d
wavelength of light is given(λ)= 550nm i.e 5500A° i.e 5500 × 10⁻¹⁰m
distance between slits(d)=1.10mm=1.10 × 10⁻³m
Distance of screen from slit(D)=1.0m
so by putting these value in the formula,we get
5500 × 10⁻¹⁰ × 1.0/ 1.1 × 10⁻³ = 0.5 × 10⁻³ i.e 0.5mm
hope it helps!
wavelength of light is given(λ)= 550nm i.e 5500A° i.e 5500 × 10⁻¹⁰m
distance between slits(d)=1.10mm=1.10 × 10⁻³m
Distance of screen from slit(D)=1.0m
so by putting these value in the formula,we get
5500 × 10⁻¹⁰ × 1.0/ 1.1 × 10⁻³ = 0.5 × 10⁻³ i.e 0.5mm
hope it helps!
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