please solve this question
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1. p (x) = 2x³-3kx²+4x-5
Let αlpha, beta, gamma be the zeroes of p (x). We know There sum is -b/a.
Sum of the zeroes = 6 (Given)
So,
alpha+ beta+ gamma = 6
-(-3k)/2 = 6
3k = 12
k = 4 (ans)
2. p(x) = 5x²+13x+ k
Given one zero is reciprocal of other.
Zeroes be x and 1/x
To find value of k -
Product of roots of an equation = c/a
=> x * 1/x = k/5
=> 1 = k/5 => k = 5 (ans)
Let αlpha, beta, gamma be the zeroes of p (x). We know There sum is -b/a.
Sum of the zeroes = 6 (Given)
So,
alpha+ beta+ gamma = 6
-(-3k)/2 = 6
3k = 12
k = 4 (ans)
2. p(x) = 5x²+13x+ k
Given one zero is reciprocal of other.
Zeroes be x and 1/x
To find value of k -
Product of roots of an equation = c/a
=> x * 1/x = k/5
=> 1 = k/5 => k = 5 (ans)
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