Question

Please solve this question.​

Answer 1

Answer:

$\frac{ \frac{ {b}^{ - 21} }{ {c}^{ - 15} } }{ \frac{ {b }^{ - 15} }{ {c}^{ - 15} } } = {b}^{ - 6} {c}^{0} \\ \\ compare - \\ \\ x = - 6 \: \: \: and \: \: \: y = 0 \\ \\ l.h.s. = x + y + 6 = - 6 + 0 + 6 = 0$

Hence proved