Question

Please solve this question​

Answer 1

HeY CuRiOuS

2Na₂S₂O₃ + I₂ → Na₂S₄O₆ 2NaI 

Oxidation of S in S₂O₃⁻² = 2 

Oxidation Number of S in S₄O₆⁻² = 5/2

Again,    

2S₂O₃⁻² → S₄O₆⁻² 

For 2 Moles of S₂O₃⁻²

 

Change in Oxidation number=

4x5/2 - 2x2x2 = 2

For 1 Mole it'll be = 2/2 = 1 

∴ Equivalent Mass of  Na₂S₂O₃=

• Molar Mass/Change in Oxi. no.→158/1=158

Hope it helps...

Answer 2

Explanation:

option c is correct hope it is helpful