Question

please solve this question​

Answer 1

Answer:

Given,

∠AOY=∠YOC                       .....(i)

∠COX=∠XOB                       .....(ii)

∠XOY = ∠YOC + ∠COX          .....(iii)

⇒∠XOY = ∠XOB + ∠AOY       ....(iv)  (from i and ii)

By adding (iii) and (iv),

2∠XOY = ∠YOC+∠COX+∠XOB+∠AOY

⇒2∠XOY = 180°    (∵∠YOC, ∠COX, ∠XOB, ∠AOY are located on same line)

⇒∠XOY = 180° ÷ 2

⇒∠XOY = 90°

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Answer 2

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