please solve this question
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use loga+logb=logab
logcot1+logcot2+......... . . . . . .. logcot89=log(cot1*cot2......*cot89)
cot1=tan89
cot2=tan88
and so on
cot45=1
hence on simplifying u get log(1) which is 0
logcot1+logcot2+......... . . . . . .. logcot89=log(cot1*cot2......*cot89)
cot1=tan89
cot2=tan88
and so on
cot45=1
hence on simplifying u get log(1) which is 0
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