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❇️ consider AB//CD
Angle ADC= 50°
Angle BAD = 180- 50 = 130°
Angle BCD = 70°
Angle CBA = 180-70= 110°
Angle E = 180-(Angle A +Angle B)/2 = 60°
Angle G= 180- ( Angle D +Angle C)/2 =
120°
Angle H =180- ( Angle B+ Angle C)/2=
90°
Angle F = 180-(Angle A + Angle D)/2= 90°
Hence Proved Quadrilateral EFGH is a Cyclic
Angle E +Angle F +Angle G + Angle H= 360°
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Meiko bas itna hi aata hai
Pta nhi sahi hai ya galat ^^"
Aur vo dusre wale mein apna name dekho = IWonU xD xD
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