Math, asked by amar414, 9 months ago

please solve this question​

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Answers

Answered by Jahnavijaiswal
0

Answer:

none of these ................

...

.

Answered by pranjaygupta
0

Answer:

(a) 49

Step-by-step explanation:

(2x+3y+z)^2 = 4x^2+9y^2+z^2+12xy+4xz+6yz

(2x+3y+z)^2 = 108+4(54) = 324

2x+3y+z = 18

x=3,y=2,z=6

x^2+y^2+z^2 = 9+4+36 = 49

hope it helps u

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