please solve this question....
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Answer:
y-3(y3-2y2-9y+18) y2+y-6
y3-3y2
- +
..............
y2-9y
y2-3y
- +
.......................
-6y+18
-6y+18
+ -
... .............
0
y2+y-6
y2+3y-2y-6
y(y+3)-2(y+3)
(y+3)(y-2)=0
either y+3=0
or. y-2=0
y=-3 and y=2
Answered by
1
clearly othe two factors are (y+3) and (y-2)
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