Math, asked by 0911nidhi, 11 months ago

please solve this question....

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Answers

Answered by gargnidhi648
1

Answer:

y-3(y3-2y2-9y+18) y2+y-6

y3-3y2

- +

..............

y2-9y

y2-3y

- +

.......................

-6y+18

-6y+18

+ -

... .............

0

y2+y-6

y2+3y-2y-6

y(y+3)-2(y+3)

(y+3)(y-2)=0

either y+3=0

or. y-2=0

y=-3 and y=2

Answered by avii369
1

clearly othe two factors are (y+3) and (y-2)

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