Math, asked by redkargauri, 9 months ago

Please solve this question​

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Answers

Answered by praveenspk08122004
0

Step-by-step explanation:

add

secx+tanx+secx-tanx/secx^2-tanx^2(sec2-tan2=1)

=2secx

=2/cosx

Mark it is not

Answered by Anonymous
0

Answer:

1/(sec x-tan x)+1/(sec x+tan x)

Adding this one. we get,

sec x+tan x+sec x-tan x/sec^2x-tan^2x

2sec x/1

2sec x

2/cos x

________________________

Identities used

  • sec^2x-tan^2x=1
  • sec x=1/cos x.
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