Question

Please solve this question......​

Answer 1

Answer:

The athlete should perspire 319.09 g of H2O in order to avoid any storage of energy in body.

Explanation:

Energy supplied to athlete by consuming 100 g glucose = 1560 kJ

Energy utilized in event = 50/100 x

1560 = 780 KJ

Energy left as excess in body = 1560 - 780 = 780 kJ

Since 44 kJ energy used to evaporate = 18 g H2O

780 kJ energy used to evaporate = (18 x 780)/44 g H2O

= 319.09 g

Thus, athlete should perspire 319.09 g of H2O in order to avoid any storage of energy in body.

Read the detailed answer on :

https://www.sarthaks.com/284236/athlete-given-glucose-c6h12o6-energy-equivalent-utilizes-percent-this-gained-energy-event

Sincerely,

H S