Question

Please solve this question​

Answer 1

Answer:

AS THE ASKED TRIANGLE ARE SIMILAR BECAUSE GIVEN IN THE QUESTION

USING THEOREM THAT RATIO OF AREAS OF TRIANGLE ARE EQUAL TO THE SQUARE OF THE RATIO OF THEIR SIDES.

AR(ACE) / AR(BCE) = (AC/BC)²

= SINCE AC IS THE DIAGONAL SO,

AC = BC√2

AR(ACE)/AR(BCE) = (BC√2/BC)²

RHS

2/1

NOW,

AR(BCE) = 1/2 AR(ACE)

HENCE PROVED!!!

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