please solve this question
Attachments:
Answers
Answered by
0
cos θ + sin θ = √2 cos θ
squaring on both side, we get......
cos²θ + sin²θ + 2cosθsinθ = 2cos²θ
2sinθcosθ = 2cos²θ - cos²θ - sin²θ
2sinθcosθ = cos²θ - sin²θ
2sinθcosθ = (cosθ+sinθ) (cosθ - sinθ)
2sinθcosθ = (√2 cosθ) (cosθ - sinθ)
2sinθcosθ/√2 cosθ = cosθ - sinθ
√2 sinθ = cosθ - sinθ
if u feel this answer is write then mark it brainliest answer
Similar questions