Question

please solve this question ​

Answer 1

Step-by-step explanation:

g(x)=I+x-[x]. f(x)={-1,x<0 or0,x=0 or1,x>0

=>f(g(x))={-1g(x)<0

{0,g(x)=0

{1,g(x)>0

=>. {-1. 1+{x}<0. => {x}<0

{0. 1+{x}=0. => {x}=-1

{1. 1+{x}>0. => {x}=1

f(g(x))= b)1