Math, asked by prathampatel1954, 7 months ago

Please solve this question

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Answered by sprao53413

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Answer:

Sin^2 36°sin^72°sin^2 108°sin^2 324°

Sin^2 36°cos^2 18°cos^2 18°sin^2 36°

[Sin36°cos 18°]^4={[10-2v5][10+2v5]/256} ^2

=(100-20)^2 /(256) ^2 =(80/256) ^2 =(5/16) ^2

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