Question

please solve this question​

Answer 1

Answer:

Step-by-step explanation:

(x^a/x^b)^(b+c-a)

we know that

a^m/a^n=a^(m-n)

a^m*a^n=a^(m+n)

so

x^a/x^b=x^(a-b)

x^((a-b)*(b+c-a))

x^(ab-a^2-b^2-bc+ab)

then

(x^c/x^a)^(c+a-b)=x^((c-a)*(c+a-b))=x^(c^2+ac-bc-ac-a^2+ab))

then

(x^a/x^b)^(a+b-c)=x^((a-b)*(a+b-c))=x^(a^2+ab-ac-ab-b^2+bc)

now

=x^(2ab-a^2-b^2-bc+c^2-bc-a^2+a^2-ac-b^2+bc)

=x^(2ab-a^2-2b^2-bc+c^2)